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12n^2+6n-168=0
a = 12; b = 6; c = -168;
Δ = b2-4ac
Δ = 62-4·12·(-168)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-90}{2*12}=\frac{-96}{24} =-4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+90}{2*12}=\frac{84}{24} =3+1/2 $
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